3j^-6/3j=1/j

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Solution for 3j^-6/3j=1/j equation: 



3j^-6/3j=1/j

We move all terms to the left:

3j^-6/3j-(1/j)=0



Domain of the equation: 3j!=0

j!=0/3

j!=0

j∈R





Domain of the equation: j)!=0

j!=0/1

j!=0

j∈R



We add all the numbers together, and all the variables

3j^-6/3j-(+1/j)=0

We add all the numbers together, and all the variables

3j-6/3j-(+1/j)=0

We get rid of parentheses

3j-6/3j-1/j=0

We calculate fractions


3j+(-6j)/3j^2+(-3j)/3j^2=0

We multiply all the terms by the denominator


3j*3j^2+(-6j)+(-3j)=0

Wy multiply elements

9j^3+(-6j)+(-3j)=0

We get rid of parentheses

9j^3-6j-3j=0

We do not support ejpression: j^3

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